A sequence has rule (a_n=5n^2+2). Which term is (127)?
Answer and explanation
Correct answer: 5th
To obtain the value 127, set \(5n^2+2=127\). This gives \(5n^2=125\), so \(n^2=25\) and \(n=5\). Since a term number is a positive integer, the correct answer is the 5th term. The 4th term is \(5\times4^2+2=82\), not 127. Exam tip: equate the given value to \(a_n\) first, then solve for \(n\).
Frequently asked questions
What is the correct answer to this question?
5th
Why is this the correct answer?
To obtain the value 127, set \(5n^2+2=127\). This gives \(5n^2=125\), so \(n^2=25\) and \(n=5\). Since a term number is a positive integer, the correct answer is the 5th term. The 4th term is \(5\times4^2+2=82\), not 127. Exam tip: equate the given value to \(a_n\) first, then solve for \(n\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.
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