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A sequence has (a_n=2n^3-3n). What is the value of (a_5)?

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Answer and explanation

Correct answer: 235

Given \(a_n=2n^3-3n\), substitute \(n=5\): \(a_5=2(5)^3-3(5)=2\times125-15=250-15=235\). Hence, 235 is correct. 250 is only the value of \(2(5)^3\); the term \(3\times5\) must still be subtracted. Exam tip: evaluate the power first, then multiply and subtract.

Related tags

Sequences And ProgressionsNth TermSubstitutionCubic SequenceAlgebraic Expressions

Frequently asked questions

What is the correct answer to this question?

235

Why is this the correct answer?

Given \(a_n=2n^3-3n\), substitute \(n=5\): \(a_5=2(5)^3-3(5)=2\times125-15=250-15=235\). Hence, 235 is correct. 250 is only the value of \(2(5)^3\); the term \(3\times5\) must still be subtracted. Exam tip: evaluate the power first, then multiply and subtract.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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