If (x=\sqrt{11}) then what is (x^2+5)?
Given \(x=\sqrt{11}\), we get \(x^2=(\sqrt{11})^2=11\). Therefore, \(x^2+5=11+5=16\), so option B is correct. \(121\) would result from squaring 11 itself, but here \(\sqrt{11}\) is being squared. Exam tip: squaring a square root gives the original non-negative number.