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Which quadratic expression is obtained from ((x-4)(x+2))?कौन-सा द्विघात व्यंजक ((x-4)(x+2)) से प्राप्त होता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x^2-2x-8\)\(x^2-2x-8\)
Use the distributive property: \((x-4)(x+2)=x(x+2)-4(x+2)=x^2+2x-4x-8=x^2-2x-8\). Therefore, the correct expression is \(x^2-2x-8\). In \(x^2+6x-8\), the negative sign of \(-4x\) has been handled incorrectly. Exam tip: write all four products first, then combine like terms.वितरण गुण का प्रयोग करें: \((x-4)(x+2)=x(x+2)-4(x+2)=x^2+2x-4x-8=x^2-2x-8\)। अतः सही व्यंजक \(x^2-2x-8\) है। \(x^2+6x-8\) में \(-4x\) के ऋण चिह्न को गलत लिया गया है। परीक्षा टिप: पहले चारों गुणनफल लिखें, फिर समान पदों को मिलाएँ।
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