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Class 9MathematicsExploring Algebraic IdentitiesQuadratic expressionsHard
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The factors of (x^2+px+21) are ((x+3)(x+7)). What is the value of (p)?

Answer and explanation

Correct answer: (10)

((x+3)(x+7)=x^2+10x+21), so (p=10). In exams the middle term comes from the sum of the constants.

Related tags

Quadratic ExpressionsUnknown CoefficientFactorisationExploring Algebraic IdentitiesMathematicsClass 9 Mcq
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  1. 1Which expression can be factorised using the difference-of-cubes identity?
  2. 2What will be the factorised form of (r^2-2rs+s^2)?
  3. 3Which expression can be factorised directly using the identity for the difference of two squares?
  4. 4Which expression can be factorised directly using the difference-of-squares identity \(a^2-b^2=(a-b)(a+b)\)?
  5. 5Which expression is a quadratic expression?
  6. 6Based on the powers of the variable \(x\) in the polynomial \(5x^2-3x+7\), what is the degree of this expression?
  7. 7If a, b and c are constants, which condition is necessary for \(ax^2+bx+c\) to be a quadratic expression in x?
  8. 8If a quadratic expression has the general form \(ax^2+bx+c\), which condition on \(a\) is necessary for it to be quadratic?
  9. 9Which of the following expressions represents the square of the difference of two terms?
  10. 10Which of the following quadratic expressions can be factorised using the identity for the difference of two squares?
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