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A student wrote \((x+4)^2\) as \(x^2+16\). Which term is missing from the expansion?एक विद्यार्थी ने
\((x+4)^2\) को \(x^2+16\) लिखा। उसके विस्तार में कौन-सा पद छूट गया है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(8x\)\(8x\)
Use \((a+b)^2=a^2+2ab+b^2\). Here, \(2\times x\times4=8x\), so the expansion is \(x^2+8x+16\). Choosing \(4x\) misses the factor 2. Exam tip: always check the middle term while expanding a square.पहचान \((a+b)^2=a^2+2ab+b^2\) लगाएँ। यहाँ \(2\times x\times4=8x\) है, इसलिए सही विस्तार \(x^2+8x+16\) होगा। \(4x\) में 2 का गुणन छूट जाता है। परीक्षा टिप: वर्ग के विस्तार में मध्य पद अवश्य जाँचें।
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