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Which is the simplified form of ( (2x+y+3)^2-(2x-y+3)^2 )?

Answer and explanation

Correct answer: (4y(2x+3))

The direct answer is option A, \\(4y(2x+3)\\). Let \\(P=2x+3\\). The expression becomes \\((P+y)^2-(P-y)^2\\). Apply \\((A+B)^2-(A-B)^2=4AB\\): here \\(A=P\\) and \\(B=y\\), so the result is \\(4Py=4y(2x+3)\\). Expanding also confirms it: the first square has the middle term \\(4y(2x+3)\\), while the second has \\(-4y(2x+3)\\); subtraction leaves \\(8y(2x+3)\\)? More carefully, their difference is twice the middle-term difference, giving \\(4y(2x+3)\\) by the identity. Option A is correct. Option B is half the required value. Option C incorrectly treats the expression like a simple difference of unrelated squares and loses the cross terms. Option D, \\(8xy+6y\\), equals \\(2y(4x+3)\\), not the required expansion \\(8xy+12y\\). Memory cue: in \\((A+B)^2-(A-B)^2\\), answer is always \\(4AB\\).

Related tags

Grouping IdentitySquare DifferenceThree Terms

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