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Find the constant term in the expansion of \((3x-2)(3x+6)\).\((3x-2)(3x+6)\) के विस्तार में स्थिर पद (constant term) ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-12\)\(-12\)
The constant term is obtained by multiplying the constant parts of the two binomials.
In \((3x-2)(3x+6)\), the constants are \(-2\) and \(6\). So the constant term is
\[
(-2)\cdot 6=-12.
\]
Therefore the constant term is \(-12\).स्थिर पद दोनों द्विपदों के स्थिर पदों को गुणा करके मिलता है।
\((3x-2)(3x+6)\) में स्थिर पद \(-2\) और \(6\) हैं। अतः स्थिर पद होगा:
\[
(-2)\cdot 6=-12.
\]
इसलिए स्थिर पद \(-12\) है।
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