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Let a = x + y. If x + y = 5, what is the correct value of (x+y+z)² − (x+y−z)²?

Answer and explanation

Correct answer: 20z

Correct answer: A, 20z. Use the identity (a+b)² − (a−b)² = 4ab. Here a = x+y and b = z. Therefore, (x+y+z)² − (x+y−z)² = 4(x+y)z. Since x+y = 5, substitute 5: 4 × 5 × z = 20z. A is correct. B is wrong because it doubles the coefficient and would require 8(x+y)z, which is not the identity. C is wrong because the two squares are not generally equal; their signs differ in the middle term. D is wrong because the z² terms cancel when the squares are subtracted. A quick expansion confirms this: both expressions contain (x+y)² and z², but one has +2(x+y)z and the other −2(x+y)z; subtracting gives 4(x+y)z. Memory cue: difference of these paired squares gives 4ab.

Related tags

Algebraic IdentitiesDifference Of SquaresSubstitutionQuadratic ExpressionsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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