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Which of the following expressions can be factorised using the identity for the sum of cubes?निम्नलिखित में से किस व्यंजक का गुणनखंडन घनों के योग की सर्वसमिका से किया जा सकता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x^3+27\)\(x^3+27\)
Here \(27=3^3\), so \(x^3+27=x^3+3^3=(x+3)(x^2-3x+9)\), which fits the sum-of-cubes identity. \(x^3-27\) is a difference of cubes. Exam tip: check whether the constant is a perfect cube.यहाँ \(27=3^3\) है, इसलिए \(x^3+27=x^3+3^3=(x+3)(x^2-3x+9)\)। \(x^3-27\) घनों का अंतर है। परीक्षा में स्थिर पद को पूर्ण घन जाँचें।
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