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Find the constant term in \((x+1)(x-3)(x+8)\).\((x+1)(x-3)(x+8)\) में नियतांक पद (constant term) निकालिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-24\)\(-24\)
The constant term of a product of polynomials is obtained by multiplying their constant terms. In \((x+1)(x-3)(x+8)\), the constant terms are \(1\), \(-3\), and \(8\). So the constant term is \(1\cdot(-3)\cdot8=-24\).बहुपदों के गुणनफल में नियतांक पद उनके नियतांक पदों को गुणा करके मिलता है। \((x+1)(x-3)(x+8)\) में नियतांक पद \(1\), \(-3\) और \(8\) हैं। इसलिए नियतांक पद \(1\cdot(-3)\cdot8=-24\) है।
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