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Simplify \((6x+1)^2-(6x-1)^2\).\((6x+1)^2-(6x-1)^2\) को सरल कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(24x\)\(24x\)
Let \(A=6x\) and rewrite as \((A+1)^2-(A-1)^2\). Using \( (u^2-v^2)=(u-v)(u+v) \): \((A+1)^2-(A-1)^2=[(A+1)-(A-1)]\,[(A+1)+(A-1)]\). First bracket: \((A+1)-(A-1)=2\). Second bracket: \((A+1)+(A-1)=2A\). So the result is \(2\cdot2A=4A=4\cdot6x=24x\).मान लीजिए \(A=6x\) और लिखिए \((A+1)^2-(A-1)^2\). पहचान \(u^2-v^2=(u-v)(u+v)\) से: \((A+1)^2-(A-1)^2=[(A+1)-(A-1)]\,[(A+1)+(A-1)]\). पहला भाग: \((A+1)-(A-1)=2\). दूसरा भाग: \((A+1)+(A-1)=2A\). अतः \(2\cdot2A=4A=4\cdot6x=24x\).
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