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What is the value of ( (p+q)^2-(p-q)^2-4pq )?

Answer and explanation

Correct answer: (0)

The direct answer is A: 0. Apply the identity \\(p+q\\)^2-\\(p-q\\)^2=4pq. Thus the first two parts together equal 4pq. The full expression is then 4pq - 4pq = 0. By direct expansion, \\(p+q\\)^2=p^2+2pq+q^2 and \\(p-q\\)^2=p^2-2pq+q^2; subtraction cancels p² and q² and leaves 4pq. Option A is correct because the remaining term is exactly cancelled. Option B, 4pq, is only the value of the first difference before the final subtraction, so it is incomplete. Option C, 2pq, results from missing one of the two middle terms and is therefore an arithmetic error. Option D, p²-q², does not follow from this difference-of-squares expression; those terms cancel. A quick check with p = 2 and q = 1 gives 3² - 1² - 8 = 9 - 1 - 8 = 0. Memory cue: first difference gives 4pq, then the outside minus 4pq removes it completely.

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Identity VerificationZeroPq

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