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In \((x-8)(x+2)\), what are the coefficient of \(x\) and the constant term?\((x-8)(x+2)\) में \(x\) का गुणांक और स्थिर पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Coefficient of \(x\) is \(-6\), constant term is \(-16\).\(x\) का गुणांक \(-6\) है और स्थिर पद \(-16\) है।
Expand: \((x-8)(x+2)=x(x+2)-8(x+2)=x^2+2x-8x-16=x^2-6x-16\). Hence coefficient of \(x\) is \(-6\) and constant term is \(-16\).विस्तार कीजिए: \((x-8)(x+2)=x(x+2)-8(x+2)=x^2+2x-8x-16=x^2-6x-16\)। इसलिए \(x\) का गुणांक \(-6\) है और स्थिर पद \(-16\) है।
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