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If (x+y=9) and (xy=14), what is (x^2+y^2)?यदि (x+y=9) और (xy=14) है तो (x^2+y^2) कितना होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 5353
Using the identity \((x+y)^2=x^2+y^2+2xy\), we get \(x^2+y^2=(x+y)^2-2xy\). Therefore, \(x^2+y^2=9^2-2\times14=81-28=53\). Option 81 is only the value of \((x+y)^2\); subtracting \(2xy\) is necessary. Exam tip: when \(x+y\) and \(xy\) are given, apply this identity directly to find the sum of squares.पहचान \((x+y)^2=x^2+y^2+2xy\) से \(x^2+y^2=(x+y)^2-2xy\)। अतः \(x^2+y^2=9^2-2\times14=81-28=53\)। विकल्प 81 केवल \((x+y)^2\) का मान है; उसमें से \(2xy\) घटाना आवश्यक है। परीक्षा टिप: जब \(x+y\) और \(xy\) दिए हों, तो वर्गों के योग के लिए यही पहचान सीधे लागू करें।
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