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Which of the following is the correct factorisation of \(x^2-49\)?

Answer and explanation

Correct answer: \((x-7)(x+7)\)

\(x^2-49=x^2-7^2\) is a difference of two squares. Using \(a^2-b^2=(a-b)(a+b)\), it becomes \((x-7)(x+7)\). \((x-7)^2\) would produce a middle term \(-14x\). Exam tip: recognise \(49=7^2\).

Related tags

Algebraic IdentitiesDifference Of SquaresFactorisationClass 9 MathematicsPolynomialsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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