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What is the value of ( 37^2-27^2 )?

Answer and explanation

Correct answer: (640)

Use the difference-of-squares identity \\(a^2-b^2=(a+b)(a-b)\\). The expression is \\(37^2-27^2\\), so set \\(a=37\\) and \\(b=27\\). Their sum is \\(37+27=64\\), and their difference is \\(37-27=10\\). Thus \\(37^2-27^2=64\\times10=640\\). This avoids separately finding 1369 and 729 and then subtracting them.

Therefore, option C, 640, is correct. A quick direct check is \\(37^2=1369\\) and \\(27^2=729\\); subtracting gives \\(1369-729=640\\). The other values are not equal to the difference. Recognising two squared numbers separated by a minus sign is the essential step in this problem.

Related tags

Numeric DifferenceSquare IdentityCalculation

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