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What will be the constant term in ( (x-2)(x-7) )?( (x-2)(x-7) ) में स्थिर पद क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 1414
Expanding, \((x-2)(x-7)=x^2-7x-2x+14=x^2-9x+14\). Therefore, the term without \(x\), the constant term, is \(14\). Note that \(-9\) is the coefficient of the middle term, not the constant term. Exam tip: the product of two negative numbers is positive.\((x-2)(x-7)=x^2-7x-2x+14=x^2-9x+14\)। अतः वह पद जिसमें \(x\) नहीं है, अर्थात स्थिर पद, \(14\) है। \(-9\) मध्य पद का गुणांक है, स्थिर पद नहीं। परीक्षा टिप: दो ऋणात्मक संख्याओं का गुणन धनात्मक होता है।
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