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What is the coefficient of \(x\) in ( \(x-2\)\(x-5\) )?( \(x-2\)\(x-5\) ) में \(x\) का गुणांक क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-7\)\(-7\)
Using the distributive property, \((x-2)(x-5)=x^2-5x-2x+10=x^2-7x+10\). Therefore, the coefficient of \(x\) is \(-7\). The number \(10\) is the constant term, not the coefficient of \(x\). Exam tip: in \((x-a)(x-b)\), the coefficient of \(x\) is \(-(a+b)\).वितरण गुण का प्रयोग करने पर \((x-2)(x-5)=x^2-5x-2x+10=x^2-7x+10\) मिलता है। इसलिए \(x\) का गुणांक \(-7\) है। \(10\) स्थिर पद है, \(x\) का गुणांक नहीं। परीक्षा टिप: \((x-a)(x-b)\) में \(x\) का गुणांक \(-(a+b)\) होता है।
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