In algebra tiles, an \(x^2\) tile, seven \(x\) tiles, and twelve unit tiles can show which area?

Correct answer: \(x^2+7x+12\)

Direct answer: option B, \(x^2+7x+12\). Algebra tiles represent different terms by their shapes and sizes. One square tile labelled \(x^2\) contributes \(x^2\). Seven rectangular \(x\)-tiles contribute \(x+x+x+x+x+x+x=7x\). Twelve unit tiles contribute 12. Adding the contributions gives the total area \(x^2+7x+12\). Option A swaps the coefficients of the \(x\)-term and the constant term, so it does not match the stated numbers of tiles. Option C uses a negative \(7x\) term; that would require negative or subtraction tiles, not seven ordinary positive \(x\)-tiles. Option D treats seven \(x\)-tiles as seven \(x^2\)-tiles, confusing their shapes and areas. Memory cue: count each tile type separately, attach its label, then add: one \(x^2\), seven \(x\), twelve 1s.