यदि \(f:\mathbb{R}\to\mathbb{R}\) और \(g:\mathbb{R}\to\mathbb{R}\) दोनों एकैकी हैं, तो \(g\circ f\) के बारे में सही कथन कौन सा है?

If \(f:\mathbb{R}\to\mathbb{R}\) and \(g:\mathbb{R}\to\mathbb{R}\) are both one-one, which statement about \(g\circ f\) is correct?

Explanation opens after your attempt
Correct Answer

A. यह हमेशा एकैकी हैIt is always one-one

Step 1

Concept

Suppose (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\)).

Step 2

Why this answer is correct

Since (g) is one-one, (f\(x_1\)=f\(x_2\)); since (f) is one-one, \(x_1=x_2\).

Step 3

Exam Tip

The composition of one-one functions is one-one. चरण 1: मान लें (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\))। चरण 2: (g) एकैकी है, इसलिए (f\(x_1\)=f\(x_2\)); फिर (f) एकैकी है, इसलिए \(x_1=x_2\)। चरण 3: एकैकी फलनों का संयोजन फिर एकैकी होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(f:\mathbb{R}\to\mathbb{R}\) और \(g:\mathbb{R}\to\mathbb{R}\) दोनों एकैकी हैं, तो \(g\circ f\) के बारे में सही कथन कौन सा है? / If \(f:\mathbb{R}\to\mathbb{R}\) and \(g:\mathbb{R}\to\mathbb{R}\) are both one-one, which statement about \(g\circ f\) is correct?

Correct Answer: A. यह हमेशा एकैकी है / It is always one-one. Explanation: चरण 1: मान लें (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\))। चरण 2: (g) एकैकी है, इसलिए (f\(x_1\)=f\(x_2\)); फिर (f) एकैकी है, इसलिए \(x_1=x_2\)। चरण 3: एकैकी फलनों का संयोजन फिर एकैकी होता है। / Step 1: Suppose (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\)). Step 2: Since (g) is one-one, (f\(x_1\)=f\(x_2\)); since (f) is one-one, \(x_1=x_2\). Step 3: The composition of one-one functions is one-one.

Which concept should I revise for this Mathematics MCQ?

Suppose (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\)).

What exam hint can help solve this Mathematics question?

The composition of one-one functions is one-one. चरण 1: मान लें (\(g\circ f\)\(x_1\)=\(g\circ f\)\(x_2\))। चरण 2: (g) एकैकी है, इसलिए (f\(x_1\)=f\(x_2\)); फिर (f) एकैकी है, इसलिए \(x_1=x_2\)। चरण 3: एकैकी फलनों का संयोजन फिर एकैकी होता है।