If R is symmetric, which statement about A×A−R is correct?
Answer and explanation
Correct answer: It will also be symmetric
Let S=(A×A)−R be the complement of R in A×A. To test symmetry, assume (a,b)∈S, so (a,b)∉R. If (b,a) were in R, then symmetry of R would imply (a,b)∈R, contradicting the assumption. Therefore (b,a)∉R and hence (b,a)∈S. Thus S is symmetric. The complement need not be empty or diagonal-only, and it can be symmetric even when R is neither universal nor empty.
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What is the correct answer to this question?
It will also be symmetric
Why is this the correct answer?
Let S=(A×A)−R be the complement of R in A×A. To test symmetry, assume (a,b)∈S, so (a,b)∉R. If (b,a) were in R, then symmetry of R would imply (a,b)∈R, contradicting the assumption. Therefore (b,a)∉R and hence (b,a)∈S. Thus S is symmetric. The complement need not be empty or diagonal-only, and it can be symmetric even when R is neither universal nor empty.
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Relations and Functions. Topic: Symmetric relation.
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