If A has 5 elements, what is the number of symmetric relations on A?
Answer and explanation
Correct answer: 2¹⁵
A symmetric relation is determined by independent choices on the diagonal and on unordered pairs of distinct elements. For n elements, the number of such choices is n + n(n−1)/2 = n(n+1)/2. With n = 5, the exponent is 5×6/2 = 15. Each choice is binary: include the corresponding diagonal pair, or include both members of an off-diagonal pair; alternatively, omit it. Therefore the number of symmetric relations is 2¹⁵, so option A is correct. The exponents 20 and 25 do not count the required paired positions.
Frequently asked questions
What is the correct answer to this question?
2¹⁵
Why is this the correct answer?
A symmetric relation is determined by independent choices on the diagonal and on unordered pairs of distinct elements. For n elements, the number of such choices is n + n(n−1)/2 = n(n+1)/2. With n = 5, the exponent is 5×6/2 = 15. Each choice is binary: include the corresponding diagonal pair, or include both members of an off-diagonal pair; alternatively, omit it. Therefore the number of symmetric relations is 2¹⁵, so option A is correct. The exponents 20 and 25 do not count the required paired positions.
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Relations and Functions. Topic: Symmetric relation.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.