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If A has 5 elements, what is the number of symmetric relations on A?

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Answer and explanation

Correct answer: 2¹⁵

A symmetric relation is determined by independent choices on the diagonal and on unordered pairs of distinct elements. For n elements, the number of such choices is n + n(n−1)/2 = n(n+1)/2. With n = 5, the exponent is 5×6/2 = 15. Each choice is binary: include the corresponding diagonal pair, or include both members of an off-diagonal pair; alternatively, omit it. Therefore the number of symmetric relations is 2¹⁵, so option A is correct. The exponents 20 and 25 do not count the required paired positions.

Related tags

Symmetric RelationFinite Set CountingRelations And Functions

Frequently asked questions

What is the correct answer to this question?

2¹⁵

Why is this the correct answer?

A symmetric relation is determined by independent choices on the diagonal and on unordered pairs of distinct elements. For n elements, the number of such choices is n + n(n−1)/2 = n(n+1)/2. With n = 5, the exponent is 5×6/2 = 15. Each choice is binary: include the corresponding diagonal pair, or include both members of an off-diagonal pair; alternatively, omit it. Therefore the number of symmetric relations is 2¹⁵, so option A is correct. The exponents 20 and 25 do not count the required paired positions.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Relations and Functions. Topic: Symmetric relation.

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