Which is the range of (\cos \theta)?
The range of (\cos \theta) is ([-1,1]). (\sin \theta) and (\cos \theta) have the same range.
View question detailsMuft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
SubjectsMathematics
TOPIC PRACTICE
Up to 20 questions from this page. Select your focus, then start.
The range of (\cos \theta) is ([-1,1]). (\sin \theta) and (\cos \theta) have the same range.
View question details\(\tan\theta=\dfrac{\sin\theta}{\cos\theta}\). For values of \(\theta\) where \(\cos\theta\ne0\), \(\tan\theta\) can take every real value. Hence its range is \(( -\infty,\infty )\). The interval \([-1,1]\) is the range of \(\sin\theta\) and \(\cos\theta\), not \(\tan\theta\). Exam tip: the range of \(\tan\theta\) is all real numbers, although it is undefined at \(\theta=\frac{\pi}{2}+n\pi\).
View question detailsSince (\sec \theta=\frac{1}{\cos \theta}), its values do not lie inside ([-1,1]). Its range is ((-\infty,-1]\cup[1,\infty)).
View question details\(\cosec\theta=\frac{1}{\sin\theta}\). Since \(-1\leq\sin\theta\leq1\) and \(\sin\theta\neq0\), the value of \(\cosec\theta\) is either less than or equal to \(-1\), or greater than or equal to 1. At \(\sin\theta=-1\) and \(1\), we get \(\cosec\theta=-1\) and \(1\), so both endpoints are included. Option C incorrectly excludes these endpoints. Exam tip: for reciprocal trigonometric functions, check values for which the denominator becomes zero.
View question details(\cot \theta) can take all real values. (\tan \theta) and (\cot \theta) have the same range.
View question details(\tan \theta=\frac{\sin \theta}{\cos \theta}), so it is undefined when (\cos \theta=0). The denominator must not be zero.
View question details(\sec \theta=\frac{1}{\cos \theta}), so it is undefined when (\cos \theta=0). Check the denominator in reciprocal functions.
View question details(\cosec \theta=\frac{1}{\sin \theta}), so it is undefined when (\sin \theta=0). A function is not defined when the denominator is zero.
View question details(\cot \theta=\frac{\cos \theta}{\sin \theta}), so it is undefined when (\sin \theta=0). In quotient functions, identify the denominator.
View question details\(\sin(\pi+\theta)=-\sin \theta\). In the third quadrant, \(\sin \theta\) is negative.
View question details\(\cos(\pi+\theta)=-\cos \theta\). In the third quadrant, \(\cos \theta\) is negative.
View question detailsThe period of (\tan \theta) is (\pi), so (\tan(\pi+\theta)=\tan \theta). Knowing periods makes transformations easier.
View question detailsThe period of (\sin \theta) is (2\pi), so the value remains (\sin \theta). Adding a full cycle does not change (\sin \theta).
View question detailsThe cosine function has period \(2\pi\). Therefore, \(\cos(\theta+2\pi)=\cos\theta\), so \(\cos(2\pi+\theta)=\cos\theta\). The expression \(-\cos\theta\) results when \(\pi\) is added to the angle: \(\cos(\theta+\pi)=-\cos\theta\). Exam tip: Adding or subtracting any integral multiple of \(2\pi\) leaves the values of sine and cosine unchanged.
View question details\(\sin(\pi-\theta)=\sin \theta\). In the second quadrant, \(\sin \theta\) is positive.
View question details\(\cos(\pi-\theta)=-\cos \theta\). In the second quadrant, \(\cos \theta\) is negative.
View question details\(\tan(\pi-\theta)=-\tan \theta\). In the second quadrant, \(\tan \theta\) is negative.
View question details\(\sin\left(\frac{\pi}{2}-\theta\right)=\cos \theta\) is a cofunction relation. In transformations with \(\frac{\pi}{2}\), the function changes.
View question details\(\cos\left(\frac{\pi}{2}-\theta\right)=\sin \theta\). In cofunction relations, \(\sin \theta\) and \(\cos \theta\) interchange.
View question details\(\tan\left(\frac{\pi}{2}-\theta\right)=\cot \theta\). The cofunction of \(\tan \theta\) is \(\cot \theta\).
View question detailsQUIZ COMPLETE