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What is the range of \(\tan \theta\)?

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Answer and explanation

Correct answer: \(( -\infty,\infty )\)

\(\tan\theta=\dfrac{\sin\theta}{\cos\theta}\). For values of \(\theta\) where \(\cos\theta\ne0\), \(\tan\theta\) can take every real value. Hence its range is \(( -\infty,\infty )\). The interval \([-1,1]\) is the range of \(\sin\theta\) and \(\cos\theta\), not \(\tan\theta\). Exam tip: the range of \(\tan\theta\) is all real numbers, although it is undefined at \(\theta=\frac{\pi}{2}+n\pi\).

Tags

trigonometric functionsrange of tangenttangent functionclass 11 mathematicsreal numbers

Frequently asked questions

What is the correct answer to this question?

\(( -\infty,\infty )\)

Why is this the correct answer?

\(\tan\theta=\dfrac{\sin\theta}{\cos\theta}\). For values of \(\theta\) where \(\cos\theta\ne0\), \(\tan\theta\) can take every real value. Hence its range is \(( -\infty,\infty )\). The interval \([-1,1]\) is the range of \(\sin\theta\) and \(\cos\theta\), not \(\tan\theta\). Exam tip: the range of \(\tan\theta\) is all real numbers, although it is undefined at \(\theta=\frac{\pi}{2}+n\pi\).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.

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