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Hard · Level 36 · graphs,cosine functions,trigonometric values,reflectionView options
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Question 1ExpertLevel 33
What is the range of the function \(f(x)=\cos x\) when \(x\in[0,\pi]\)?
Correct answer: A
On the interval \([0,\pi]\), \(\cos x\) decreases continuously from \(\cos 0=1\) to \(\cos\pi=-1\). Since both endpoints are included, every value from \(-1\) to \(1\) is attained, so the range is \([-1,1]\). Exam tip: for cosine over \([0,\pi]\), check the endpoint values first; they give the complete range.
Which of the following is the range of the function \(y=\frac{1}{2+\sin x}\)?
Correct answer: A
Since \(-1\le\sin x\le1\), the denominator lies from 1 to 3. Taking reciprocals of positive values reverses the bounds, giving \(\frac13\le y\le1\). Exam tip: check whether endpoint values are attained.
For the graph of the function \(y=-\cos x\), what is the value of \(y\) when \(x=0\)?
Correct answer: A
Substituting \(x=0\) gives \(y=-\cos 0=-1\), since \(\cos 0=1\). Option B omits the negative sign and gives the value of \(\cos 0\), not \(-\cos 0\). Exam tip: evaluate the standard trigonometric value first, then apply any sign outside the function.
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