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Which of the following is the range of the function \(y=\frac{1}{2+\sin x}\)?

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Answer and explanation

Correct answer: \(\left[\frac{1}{3},1\right]\)

Since \(-1\le\sin x\le1\), the denominator lies from 1 to 3. Taking reciprocals of positive values reverses the bounds, giving \(\frac13\le y\le1\). Exam tip: check whether endpoint values are attained.

Tags

trigonometric functionsrange of functionssine functionreciprocal functiongraphsclass 11 mathematics

Frequently asked questions

What is the correct answer to this question?

\(\left[\frac{1}{3},1\right]\)

Why is this the correct answer?

Since \(-1\le\sin x\le1\), the denominator lies from 1 to 3. Taking reciprocals of positive values reverses the bounds, giving \(\frac13\le y\le1\). Exam tip: check whether endpoint values are attained.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Domain, range, and graphs of trigonometric functions.

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