On (A={1,2,3}), (R={(a,b):a<b}). Is (R) reflexive or not?
Step 1: Reflexivity needs ((1,1),(2,2),(3,3)). Step 2: No number satisfies (a<a). Step 3: The relation (<) is not reflexive.
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SubjectsMathematics
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Step 1: Reflexivity needs ((1,1),(2,2),(3,3)). Step 2: No number satisfies (a<a). Step 3: The relation (<) is not reflexive.
View question detailsStep 1: The key idea of a reflexive relation is being related to itself. Step 2: This means ((x,x)\in R) for every (x). Step 3: Remembering the definition helps solve such questions quickly.
View question detailsStep 1: For (0) and (1), the pairs ((0,0)) and ((1,1)) are required. Step 2: ((0,0)) is already present, but ((1,1)) is missing. Step 3: Add the missing diagonal pair.
View question detailsStep 1: In a reflexive relation, every element is related to itself. Step 2: Since (r) is in (A), ((r,r)) must be present. Step 3: Pairs with different elements are not compulsory.
View question detailsStep 1: It contains the self-pair of every element. Step 2: It has no extra pairs, so it is the smallest reflexive relation. Step 3: This is also the identity relation on the set.
View question detailsStep 1: Reflexivity is checked through self-pairs. Step 2: For every element (a), ((a,a)) must be present. Step 3: In exams, list the diagonal pairs directly.
View question detailsStep 1: The required pairs for (A) are ((1,1),(2,2),(3,3)). Step 2: All three are present in (R). Step 3: Other pairs do not affect reflexivity.
View question detailsStep 1: The elements (1,2,3) need their self-pairs. Step 2: ((1,1)) and ((3,3)) are present, but ((2,2)) is missing. Step 3: Focus on the missing self-pair.
View question detailsStep 1: For reflexivity, test an element with itself. Step 2: For every (a), (a-a=0), so ((a,a)\in R). Step 3: Put (b=a) in the condition to check quickly.
View question detailsStep 1: For reflexivity, put ((a,a)) into the condition. Step 2: (a+a=2a) is always even, so every ((a,a)) is included. Step 3: Checking the self-pair condition is the fastest method.
View question detailsStep 1: For ((a,a)), the sum is (a+a=2a). Step 2: (2a) is always even, not odd. Step 3: So no self-pair satisfies the condition.
View question detailsStep 1: Reflexivity needs ((a,a)) for every (a). Step 2: Every non-zero number divides itself, so ((a,a)) is included. Step 3: In divisibility questions, remember (a\mid a) first.
View question detailsStep 1: For reflexivity, putting (b=a) would require (a=a+1). Step 2: This is not true for any number. Step 3: A condition that gives no self-pair is not reflexive.
View question detailsStep 1: The singleton set has only (10). Step 2: Reflexivity requires ((10,10)). Step 3: The definition stays the same even for small sets.
View question detailsStep 1: (A\times A) has (4) pairs. Step 2: ((1,1)) and ((2,2)) are compulsory, while the remaining (2) pairs are optional. Step 3: Hence the number is (2^2=4).
View question detailsStep 1: Total pairs are (3^2=9). Step 2: The (3) self-pairs are compulsory, so (9-3=6) pairs are optional. Step 3: Each optional pair has two choices, so (2^6) relations are possible.
View question detailsStep 1: In a reflexive relation, each element is related to itself. Step 2: Since (3) is an element of the set, ((3,3)) is compulsory. Step 3: Pairs with other elements are not compulsory.
View question detailsStep 1: Reflexivity only requires all self-pairs. Step 2: All four required self-pairs are present. Step 3: Whether extra pairs exist or not, the relation is reflexive.
View question detailsStep 1: Reflexive means returning to the same element. Step 2: Therefore every element must be related to itself. Step 3: For definition-based questions, remember this key sentence.
View question detailsStep 1: All three self-pairs needed for reflexivity are present. Step 2: ((2,1)) is an extra pair and does not remove reflexivity. Step 3: Do not worry about extra pairs; check the required pairs.
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