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Why is (f:\mathbb{R}\to\mathbb{R}), (f(x)=\sin x+\cos x), not one-one on all of (\mathbb{R})?

Answer and explanation

Correct answer: Because it is periodic

Step 1: (\sin x+\cos x) can be written as (\sqrt{2}\sin(x+\frac{\pi}{4})). Step 2: It is periodic, so the same value repeats at many different (x)-values. Step 3: A periodic function is generally not one-one on the whole real domain.

Related tags

Trigonometric FunctionPeriodicNot One-OneSine CosineOne One FunctionRelations And FunctionsMathematicsClass 12 Mcq

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