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Class 12MathematicsRelations and FunctionsOne-one functionExpert
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The function (f:\mathbb{R}\to\mathbb{R}) is defined by (f(x)=x-1) if (x<0) and (f(x)=x+1) if (x\ge0). What is correct about (f)?

Answer and explanation

Correct answer: (f) is one-one

Step 1: For (x<0), (f(x)<-1). Step 2: For (x\ge0), (f(x)\ge1), so the ranges of the two pieces are disjoint. Step 3: Each piece is one-one and their ranges do not overlap, so the whole function is one-one.

Related tags

Piecewise FunctionDisjoint RangesOne-One FunctionClass 12One One FunctionRelations And FunctionsMathematicsClass 12 Mcq
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10 more MCQs
  1. 1Which statement is true for a one-one function?
  2. 2If (f(2)=5) and (f(3)=5), what can be said about (f)?
  3. 3If (f:\mathbb{R}\to\mathbb{R}) and (f(x)=2x+1), what type of function is (f)?
  4. 4If (f:\mathbb{R}\to\mathbb{R}) and (f(x)=7), what type of function is (f)?
  5. 5If (f:\mathbb{R}\to[0,\infty)) and (f(x)=|x|), what type of function is (f)?
  6. 6If (f:\mathbb{R}\to(0,\infty)) and (f(x)=e^x), what type of function is (f)?
  7. 7If (f:(0,\infty)\to\mathbb{R}) and (f(x)=\log x), which statement about (f) is correct?
  8. 8If (f:\mathbb{R}\to\mathbb{R}) and (f(x)=3x-5), what follows from (f(a)=f(b))?
  9. 9Which example proves that (f(x)=x^2+1) is not one-one on real numbers?
  10. 10If (f:\mathbb{N}\to\mathbb{N}) and (f(n)=n+4), what type of function is (f)?
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