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Which condition correctly defines a one-one function \(f:A\to B\)?

Answer and explanation

Correct answer: \(f(x_1)=f(x_2)\Rightarrow x_1=x_2\)

In a one-one function, distinct inputs must have distinct images. Therefore, if \(f(x_1)=f(x_2)\), then necessarily \(x_1=x_2\); hence option A is correct. Option C is the condition for an onto function, where every element of \(B\) must have at least one preimage in \(A\). Exam tip: for one-one functions, check whether equal outputs force the inputs to be equal.

Related tags

One-One FunctionInjective FunctionRelations And FunctionsClass 12 MathematicsFunction PropertiesOne One FunctionMathematicsClass 12 Mcq

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