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Molar Mass Determination

Class 12 Chemistry के इस tag से जुड़े questions। हर question के साथ chapter, topic, level और difficulty दी गई है।

ChemistryWhich sequence is most appropriate for determining molar mass from depression in freezing point?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryFor determining the molar mass of large molecules, which method does not require measurement of very small temperature changes?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryA non-dissociated solute forms a 0.04 M solution of volume 250 mL, and the solute mass is 1.2 g. What is the molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16EasyChemistryIf 2 L of a 0.01 M solution contains 3.6 g of solute, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16EasyChemistryIf a solution has a concentration of 0.05 M and contains 2 g of solute per 250 mL of solution, what is the molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryA 500 mL solution is prepared from 3.6 g of a non-dissociated solute. Its osmotic pressure at 300 K is 0.738 atm. What is the molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryIn the osmotic pressure method, 2 g of a solute is used to prepare 1 L of solution. At 300 K, the osmotic pressure is 0.492 atm. If R = 0.082 L atm mol⁻¹ K⁻¹, what is the molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryIf the observed molar mass of a solute is 2/3 of its true molar mass, what is the van’t Hoff factor (i)?Class 12Chapter 01: Solutions7: Abnormal Molecular MassLevel 16MediumChemistryWhich colligative property is most suitable for determining the molar mass of polymers with very high molar masses?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryWhile determining molar mass by the lowering of vapour pressure method, if a solute undergoes complete dimerisation in benzene, how will its observed molar mass compare with its true molar mass?Class 12Chapter 01: Solutions7: Abnormal Molecular MassLevel 16MediumChemistryWhich colligative property is most suitable for determining the molar mass of a polymer with very high molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16EasyChemistryWhich colligative property is most suitable for determining the molar mass of polymers with very large molecules?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16EasyChemistryWhich colligative property is generally preferred for determining the molar mass of high-molar-mass solutes such as proteins and polymers?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16EasyChemistryWhen 4 g of a non-dissociated solute is dissolved in 200 g of solvent, the elevation in boiling point is 0.104 K. If K_b = 0.52 K kg mol^-1, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryWhen 1.5 g of a non-dissociated solute is dissolved in 150 g of solvent, the elevation in boiling point is 0.104 K. If K_b = 0.52 K kg mol^-1, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 16MediumChemistryIf 0.5 g of a solute dissolved in 50 g of water produces ΔT_f = 0.186 K, what is its molar mass when K_f = 1.86 K kg mol⁻¹?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18MediumChemistryIn a solution, 6 g of a non-dissociated solute gives a molality of 0.12 m. If the solvent mass is 0.5 kg, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18MediumChemistryIf 1.2 g of a solute forms a 0.02 m solution and the solvent mass is 0.5 kg, what is the molar mass of the solute?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18MediumChemistryWhen 4 g of a non-dissociated solute is used to prepare 500 mL of solution, its osmotic pressure at 300 K is 0.984 atm. What is the molar mass? Take R = 0.082 L atm mol⁻¹ K⁻¹.Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18MediumChemistryA 1.8 g sample of a non-dissociated solute is used to make 250 mL of solution. At 300 K, the osmotic pressure is 0.738 atm. If R = 0.082 L atm mol⁻¹ K⁻¹, what is the molar mass?Class 12Chapter 01: Solutions6: Molar Mass DeterminationLevel 18Medium

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