सूत्र (^{n}C_r=\frac{n!}{r!(n-r)!}) की व्युत्पत्ति में (r!) से भाग क्यों दिया जाता है?

Why do we divide by (r!) while deriving (^{n}C_r=\frac{n!}{r!(n-r)!})?

Explanation opens after your attempt
Correct Answer

A. क्योंकि (r) वस्तुओं की व्यवस्था नहीं गिनी जातीBecause arrangements of (r) objects are not counted

Step 1

Concept

In combinations order is not important so (r!) duplicate arrangements are removed. In exams divide when order is ignored.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि (r) वस्तुओं की व्यवस्था नहीं गिनी जाती / Because arrangements of (r) objects are not counted. In combinations order is not important so (r!) duplicate arrangements are removed. In exams divide when order is ignored.

Step 3

Exam Tip

Combination में क्रम का महत्व नहीं होता इसलिए (r!) duplicate arrangements हटाए जाते हैं। परीक्षा में order ignored हो तो division याद रखें।

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Mathematics Answer, Explanation and Revision Hints

सूत्र (^{n}C_r=\frac{n!}{r!(n-r)!}) की व्युत्पत्ति में (r!) से भाग क्यों दिया जाता है? / Why do we divide by (r!) while deriving (^{n}C_r=\frac{n!}{r!(n-r)!})?

Correct Answer: A. क्योंकि (r) वस्तुओं की व्यवस्था नहीं गिनी जाती / Because arrangements of (r) objects are not counted. Explanation: Combination में क्रम का महत्व नहीं होता इसलिए (r!) duplicate arrangements हटाए जाते हैं। परीक्षा में order ignored हो तो division याद रखें। / In combinations order is not important so (r!) duplicate arrangements are removed. In exams divide when order is ignored.

Which concept should I revise for this Mathematics MCQ?

In combinations order is not important so (r!) duplicate arrangements are removed. In exams divide when order is ignored.

What exam hint can help solve this Mathematics question?

Combination में क्रम का महत्व नहीं होता इसलिए (r!) duplicate arrangements हटाए जाते हैं। परीक्षा में order ignored हो तो division याद रखें।