असमानता \(\frac{7-2x}{4}\ge -3\) का संख्या रेखा पर हल कौन-सा है?
Which is the number line solution of \(\frac{7-2x}{4}\ge -3\)?
Explanation opens after your attempt
Correct Answer
A. \(x\le\frac{19}{2}\), \(\frac{19}{2}\) पर बंद बिंदु और बाईं ओर\(x\le\frac{19}{2}\), closed dot at \(\frac{19}{2}\) shaded left
Concept
\(7-2x\ge -12\) gives \(-2x\ge -19\), so \(x\le\frac{19}{2}\). In exams, reverse the sign when dividing by a negative.
Why this answer is correct
The correct answer is A. \(x\le\frac{19}{2}\), \(\frac{19}{2}\) पर बंद बिंदु और बाईं ओर / \(x\le\frac{19}{2}\), closed dot at \(\frac{19}{2}\) shaded left. \(7-2x\ge -12\) gives \(-2x\ge -19\), so \(x\le\frac{19}{2}\). In exams, reverse the sign when dividing by a negative.
Exam Tip
\(7-2x\ge -12\) से \(-2x\ge -19\), इसलिए \(x\le\frac{19}{2}\)। परीक्षा में ऋणात्मक से भाग देने पर चिन्ह पलटें।
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