फलन (f(x)=\frac{\sqrt{x+1}}{x-4}) का प्रांत कौन सा है?
Which is the domain of (f(x)=\frac{\sqrt{x+1}}{x-4})?
Explanation opens after your attempt
A. \([-1,\infty\)-{4})
Concept
For the square root \(x+1\ge 0\) and for the denominator \(x\ne 4\) are required. Thus the intersection is \([-1,\infty\)-{4}).
Why this answer is correct
The correct answer is A. \([-1,\infty\)-{4}). For the square root \(x+1\ge 0\) and for the denominator \(x\ne 4\) are required. Thus the intersection is \([-1,\infty\)-{4}).
Exam Tip
वर्गमूल के लिए \(x+1\ge 0\) और हर के लिए \(x\ne 4\) चाहिए। इसलिए दोनों शर्तों का प्रतिच्छेद \([-1,\infty\)-{4}) है।
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