असमानता \(2x+3\le 15\) का हल निकालने में सही क्रम कौन सा है?

Which is the correct order to solve \(2x+3\le 15\)?

Explanation opens after your attempt
Correct Answer

A. (3) घटाएं फिर (2) से भाग देंSubtract (3) then divide by (2)

Step 1

Concept

First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.

Step 2

Why this answer is correct

The correct answer is A. (3) घटाएं फिर (2) से भाग दें / Subtract (3) then divide by (2). First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.

Step 3

Exam Tip

पहले (3) घटाने पर \(2x\le 12\), फिर (2) से भाग देने पर \(x\le 6\)। उल्टे क्रम में ऑपरेशन करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(2x+3\le 15\) का हल निकालने में सही क्रम कौन सा है? / Which is the correct order to solve \(2x+3\le 15\)?

Correct Answer: A. (3) घटाएं फिर (2) से भाग दें / Subtract (3) then divide by (2). Explanation: पहले (3) घटाने पर \(2x\le 12\), फिर (2) से भाग देने पर \(x\le 6\)। उल्टे क्रम में ऑपरेशन करें। / First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.

Which concept should I revise for this Mathematics MCQ?

First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.

What exam hint can help solve this Mathematics question?

पहले (3) घटाने पर \(2x\le 12\), फिर (2) से भाग देने पर \(x\le 6\)। उल्टे क्रम में ऑपरेशन करें।