असमानता \(2x+3\le 15\) का हल निकालने में सही क्रम कौन सा है?
Which is the correct order to solve \(2x+3\le 15\)?
Explanation opens after your attempt
A. (3) घटाएं फिर (2) से भाग देंSubtract (3) then divide by (2)
Concept
First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.
Why this answer is correct
The correct answer is A. (3) घटाएं फिर (2) से भाग दें / Subtract (3) then divide by (2). First subtracting (3) gives \(2x\le 12\), then dividing by (2) gives \(x\le 6\). Use operations in reverse order.
Exam Tip
पहले (3) घटाने पर \(2x\le 12\), फिर (2) से भाग देने पर \(x\le 6\)। उल्टे क्रम में ऑपरेशन करें।
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