( \frac{(n+1)!}{(n-3)!} ) का सही विस्तार कौन सा है?
Which is the correct expansion of ( \frac{(n+1)!}{(n-3)!} )?
Explanation opens after your attempt
Correct Answer
A. ((n+1)n(n-1)(n-2))
Concept
We expand ((n+1)!) up to ((n+1)n(n-1)(n-2)(n-3)!). Therefore four factors remain.
Why this answer is correct
The correct answer is A. ((n+1)n(n-1)(n-2)). We expand ((n+1)!) up to ((n+1)n(n-1)(n-2)(n-3)!). Therefore four factors remain.
Exam Tip
((n+1)!) को ((n+1)n(n-1)(n-2)(n-3)!) तक फैलाते हैं। इसलिए चार गुणक बचते हैं।
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