अंतराल \((-\infty, -\frac{1}{2})\) संख्या रेखा पर किस असमता को दर्शाता है?

Which inequality is represented by the interval \((-\infty, -\frac{1}{2}]\) on the number line?

Explanation opens after your attempt
Correct Answer

B. \(x\le -\frac{1}{2}\)

Step 1

Concept

The square bracket shows that \(-\frac{1}{2}\) is included, and the values extend toward \(-\infty\). Hence \(x\le -\frac{1}{2}\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(x\le -\frac{1}{2}\). The square bracket shows that \(-\frac{1}{2}\) is included, and the values extend toward \(-\infty\). Hence \(x\le -\frac{1}{2}\) is correct.

Step 3

Exam Tip

वर्ग कोष्ठक बताता है कि \(-\frac{1}{2}\) शामिल है और \(-\infty\) की ओर छोटी संख्याएँ हैं। इसलिए \(x\le -\frac{1}{2}\) सही है।

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Mathematics Answer, Explanation and Revision Hints

अंतराल \((-\infty, -\frac{1}{2})\) संख्या रेखा पर किस असमता को दर्शाता है? / Which inequality is represented by the interval \((-\infty, -\frac{1}{2}]\) on the number line?

Correct Answer: B. \(x\le -\frac{1}{2}\). Explanation: वर्ग कोष्ठक बताता है कि \(-\frac{1}{2}\) शामिल है और \(-\infty\) की ओर छोटी संख्याएँ हैं। इसलिए \(x\le -\frac{1}{2}\) सही है। / The square bracket shows that \(-\frac{1}{2}\) is included, and the values extend toward \(-\infty\). Hence \(x\le -\frac{1}{2}\) is correct.

Which concept should I revise for this Mathematics MCQ?

The square bracket shows that \(-\frac{1}{2}\) is included, and the values extend toward \(-\infty\). Hence \(x\le -\frac{1}{2}\) is correct.

What exam hint can help solve this Mathematics question?

वर्ग कोष्ठक बताता है कि \(-\frac{1}{2}\) शामिल है और \(-\infty\) की ओर छोटी संख्याएँ हैं। इसलिए \(x\le -\frac{1}{2}\) सही है।