असमानता \(2x+y\leq 4\) और \(x\geq 0\), \(y\geq 0\) का सामान्य हल क्षेत्र कहाँ होगा?
Where will the common solution region of \(2x+y\leq 4\), \(x\geq 0\), and \(y\geq 0\) lie?
Explanation opens after your attempt
Correct Answer
A. प्रथम चतुर्थांश में सीमा रेखा के नीचेin first quadrant below the boundary line
Concept
\(x\geq 0\) and \(y\geq 0\) give the first quadrant. \(2x+y\leq 4\) selects the part below the line.
Why this answer is correct
The correct answer is A. प्रथम चतुर्थांश में सीमा रेखा के नीचे / in first quadrant below the boundary line. \(x\geq 0\) and \(y\geq 0\) give the first quadrant. \(2x+y\leq 4\) selects the part below the line.
Exam Tip
\(x\geq 0\) और \(y\geq 0\) प्रथम चतुर्थांश देते हैं। \(2x+y\leq 4\) रेखा के नीचे का भाग चुनता है।
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