शब्द (REPETITION) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं?

What is the total number of distinct arrangements of the letters of (REPETITION)?

Explanation opens after your attempt
Correct Answer

B. (453600)

Step 1

Concept

Here (E,T,I) are each repeated twice, so the count is (10!/(2!2!2!)). Divide by the factorial of each repeated letter.

Step 2

Why this answer is correct

The correct answer is B. (453600). Here (E,T,I) are each repeated twice, so the count is (10!/(2!2!2!)). Divide by the factorial of each repeated letter.

Step 3

Exam Tip

इसमें (E,T,I) दो-दो बार हैं, इसलिए संख्या (10!/(2!2!2!)) है। हर दोहराए अक्षर के फैक्टोरियल से भाग दें।

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शब्द (REPETITION) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं? / What is the total number of distinct arrangements of the letters of (REPETITION)?

Correct Answer: B. (453600). Explanation: इसमें (E,T,I) दो-दो बार हैं, इसलिए संख्या (10!/(2!2!2!)) है। हर दोहराए अक्षर के फैक्टोरियल से भाग दें। / Here (E,T,I) are each repeated twice, so the count is (10!/(2!2!2!)). Divide by the factorial of each repeated letter.

Which concept should I revise for this Mathematics MCQ?

Here (E,T,I) are each repeated twice, so the count is (10!/(2!2!2!)). Divide by the factorial of each repeated letter.

What exam hint can help solve this Mathematics question?

इसमें (E,T,I) दो-दो बार हैं, इसलिए संख्या (10!/(2!2!2!)) है। हर दोहराए अक्षर के फैक्टोरियल से भाग दें।