शब्द (PROBABILITY) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं?

What is the total number of distinct arrangements of the letters of (PROBABILITY)?

Explanation opens after your attempt
Correct Answer

A. (9979200)

Step 1

Concept

Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.

Step 2

Why this answer is correct

The correct answer is A. (9979200). Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.

Step 3

Exam Tip

इस शब्द में (B) और (I) दो-दो बार हैं, इसलिए संख्या (11!/(2!2!)) है। दोहराए अक्षर पहचानना पहला कदम है।

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शब्द (PROBABILITY) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं? / What is the total number of distinct arrangements of the letters of (PROBABILITY)?

Correct Answer: A. (9979200). Explanation: इस शब्द में (B) और (I) दो-दो बार हैं, इसलिए संख्या (11!/(2!2!)) है। दोहराए अक्षर पहचानना पहला कदम है। / Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.

Which concept should I revise for this Mathematics MCQ?

Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.

What exam hint can help solve this Mathematics question?

इस शब्द में (B) और (I) दो-दो बार हैं, इसलिए संख्या (11!/(2!2!)) है। दोहराए अक्षर पहचानना पहला कदम है।