शब्द (PROBABILITY) के अक्षरों की कुल भिन्न व्यवस्थाएं कितनी हैं?
What is the total number of distinct arrangements of the letters of (PROBABILITY)?
Explanation opens after your attempt
A. (9979200)
Concept
Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.
Why this answer is correct
The correct answer is A. (9979200). Here (B) and (I) are repeated twice, so the count is (11!/(2!2!)). Identifying repeated letters is the first step.
Exam Tip
इस शब्द में (B) और (I) दो-दो बार हैं, इसलिए संख्या (11!/(2!2!)) है। दोहराए अक्षर पहचानना पहला कदम है।
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