युग्म असमानता \(5\le 3x-1<2x+11\) का हल क्या है?

What is the solution of the compound inequality \(5\le 3x-1<2x+11\)?

Explanation opens after your attempt
Correct Answer

C. \(2\le x<12\)

Step 1

Concept

The first part gives \(x\ge 2\), and the second gives (x<12). Together they give \(2\le x<12\).

Step 2

Why this answer is correct

The correct answer is C. \(2\le x<12\). The first part gives \(x\ge 2\), and the second gives (x<12). Together they give \(2\le x<12\).

Step 3

Exam Tip

पहले भाग से \(x\ge 2\) और दूसरे भाग से (x<12) मिलता है। दोनों मिलकर \(2\le x<12\) देते हैं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

युग्म असमानता \(5\le 3x-1<2x+11\) का हल क्या है? / What is the solution of the compound inequality \(5\le 3x-1<2x+11\)?

Correct Answer: C. \(2\le x<12\). Explanation: पहले भाग से \(x\ge 2\) और दूसरे भाग से (x<12) मिलता है। दोनों मिलकर \(2\le x<12\) देते हैं। / The first part gives \(x\ge 2\), and the second gives (x<12). Together they give \(2\le x<12\).

Which concept should I revise for this Mathematics MCQ?

The first part gives \(x\ge 2\), and the second gives (x<12). Together they give \(2\le x<12\).

What exam hint can help solve this Mathematics question?

पहले भाग से \(x\ge 2\) और दूसरे भाग से (x<12) मिलता है। दोनों मिलकर \(2\le x<12\) देते हैं।