( \frac{(n+6)!}{(n+2)!}-\frac{(n+5)!}{(n+1)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+6)!}{(n+2)!}-\frac{(n+5)!}{(n+1)!} )?

Explanation opens after your attempt
Correct Answer

A. (4(n+5)(n+4)(n+3))

Step 1

Concept

Taking common ((n+5)(n+4)(n+3)), the difference is ((n+6)-(n+2)=4). Identify common factors first.

Step 2

Why this answer is correct

The correct answer is A. (4(n+5)(n+4)(n+3)). Taking common ((n+5)(n+4)(n+3)), the difference is ((n+6)-(n+2)=4). Identify common factors first.

Step 3

Exam Tip

सामान्य ((n+5)(n+4)(n+3)) निकालने पर अंतर ((n+6)-(n+2)=4) है। पहले समान गुणकों को पहचानें।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+6)!}{(n+2)!}-\frac{(n+5)!}{(n+1)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+6)!}{(n+2)!}-\frac{(n+5)!}{(n+1)!} )?

Correct Answer: A. (4(n+5)(n+4)(n+3)). Explanation: सामान्य ((n+5)(n+4)(n+3)) निकालने पर अंतर ((n+6)-(n+2)=4) है। पहले समान गुणकों को पहचानें। / Taking common ((n+5)(n+4)(n+3)), the difference is ((n+6)-(n+2)=4). Identify common factors first.

Which concept should I revise for this Mathematics MCQ?

Taking common ((n+5)(n+4)(n+3)), the difference is ((n+6)-(n+2)=4). Identify common factors first.

What exam hint can help solve this Mathematics question?

सामान्य ((n+5)(n+4)(n+3)) निकालने पर अंतर ((n+6)-(n+2)=4) है। पहले समान गुणकों को पहचानें।