( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!} )?

Explanation opens after your attempt
Correct Answer

D. (3(n+1)(n+2))

Step 1

Concept

The first term is ((n+3)(n+2)(n+1)) and the second is (n(n+1)(n+2)), so the difference is (3(n+1)(n+2)). Take common factors out.

Step 2

Why this answer is correct

The correct answer is D. (3(n+1)(n+2)). The first term is ((n+3)(n+2)(n+1)) and the second is (n(n+1)(n+2)), so the difference is (3(n+1)(n+2)). Take common factors out.

Step 3

Exam Tip

पहला पद ((n+3)(n+2)(n+1)) और दूसरा (n(n+1)(n+2)) है, इसलिए अंतर (3(n+1)(n+2)) है। समान गुणकों को बाहर निकालें।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!} )?

Correct Answer: D. (3(n+1)(n+2)). Explanation: पहला पद ((n+3)(n+2)(n+1)) और दूसरा (n(n+1)(n+2)) है, इसलिए अंतर (3(n+1)(n+2)) है। समान गुणकों को बाहर निकालें। / The first term is ((n+3)(n+2)(n+1)) and the second is (n(n+1)(n+2)), so the difference is (3(n+1)(n+2)). Take common factors out.

Which concept should I revise for this Mathematics MCQ?

The first term is ((n+3)(n+2)(n+1)) and the second is (n(n+1)(n+2)), so the difference is (3(n+1)(n+2)). Take common factors out.

What exam hint can help solve this Mathematics question?

पहला पद ((n+3)(n+2)(n+1)) और दूसरा (n(n+1)(n+2)) है, इसलिए अंतर (3(n+1)(n+2)) है। समान गुणकों को बाहर निकालें।