( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!} )?

Explanation opens after your attempt
Correct Answer

B. \(2n^2+2n+2\)

Step 1

Concept

The first term is ((n+2)(n+1)) and the second is (n(n-1)). Adding gives \(2n^2+2n+2\).

Step 2

Why this answer is correct

The correct answer is B. \(2n^2+2n+2\). The first term is ((n+2)(n+1)) and the second is (n(n-1)). Adding gives \(2n^2+2n+2\).

Step 3

Exam Tip

पहला पद ((n+2)(n+1)) और दूसरा (n(n-1)) है। जोड़ने पर \(2n^2+2n+2\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+2)!}{n!}+\frac{n!}{(n-2)!} )?

Correct Answer: B. \(2n^2+2n+2\). Explanation: पहला पद ((n+2)(n+1)) और दूसरा (n(n-1)) है। जोड़ने पर \(2n^2+2n+2\) मिलता है। / The first term is ((n+2)(n+1)) and the second is (n(n-1)). Adding gives \(2n^2+2n+2\).

Which concept should I revise for this Mathematics MCQ?

The first term is ((n+2)(n+1)) and the second is (n(n-1)). Adding gives \(2n^2+2n+2\).

What exam hint can help solve this Mathematics question?

पहला पद ((n+2)(n+1)) और दूसरा (n(n-1)) है। जोड़ने पर \(2n^2+2n+2\) मिलता है।