( \frac{(n+2)!}{n!}-\frac{(n+1)!}{(n-1)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+2)!}{n!}-\frac{(n+1)!}{(n-1)!} )?

Explanation opens after your attempt
Correct Answer

A. (2(n+1))

Step 1

Concept

The first term is ((n+2)(n+1)) and the second is (n(n+1)), so the difference is (2(n+1)). Take the common factor out.

Step 2

Why this answer is correct

The correct answer is A. (2(n+1)). The first term is ((n+2)(n+1)) and the second is (n(n+1)), so the difference is (2(n+1)). Take the common factor out.

Step 3

Exam Tip

पहला पद ((n+2)(n+1)) और दूसरा (n(n+1)) है, इसलिए अंतर (2(n+1)) है। समान गुणक बाहर निकालें।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+2)!}{n!}-\frac{(n+1)!}{(n-1)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+2)!}{n!}-\frac{(n+1)!}{(n-1)!} )?

Correct Answer: A. (2(n+1)). Explanation: पहला पद ((n+2)(n+1)) और दूसरा (n(n+1)) है, इसलिए अंतर (2(n+1)) है। समान गुणक बाहर निकालें। / The first term is ((n+2)(n+1)) and the second is (n(n+1)), so the difference is (2(n+1)). Take the common factor out.

Which concept should I revise for this Mathematics MCQ?

The first term is ((n+2)(n+1)) and the second is (n(n+1)), so the difference is (2(n+1)). Take the common factor out.

What exam hint can help solve this Mathematics question?

पहला पद ((n+2)(n+1)) और दूसरा (n(n+1)) है, इसलिए अंतर (2(n+1)) है। समान गुणक बाहर निकालें।