( \frac{(n!)2}{(n-1)!(n+1)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n!)2}{(n-1)!(n+1)!} )?

Explanation opens after your attempt
Correct Answer

C. \( \frac{n}{n+1} \)

Step 1

Concept

( \frac{n!}{(n-1)!}=n ) and ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), so the answer is \( \frac{n}{n+1} \). Break the ratio into two smaller parts.

Step 2

Why this answer is correct

The correct answer is C. \( \frac{n}{n+1} \). ( \frac{n!}{(n-1)!}=n ) and ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), so the answer is \( \frac{n}{n+1} \). Break the ratio into two smaller parts.

Step 3

Exam Tip

( \frac{n!}{(n-1)!}=n ) और ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), इसलिए उत्तर \( \frac{n}{n+1} \) है। अनुपात को दो छोटे भागों में तोड़ें।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n!)2}{(n-1)!(n+1)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n!)2}{(n-1)!(n+1)!} )?

Correct Answer: C. \( \frac{n}{n+1} \). Explanation: ( \frac{n!}{(n-1)!}=n ) और ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), इसलिए उत्तर \( \frac{n}{n+1} \) है। अनुपात को दो छोटे भागों में तोड़ें। / ( \frac{n!}{(n-1)!}=n ) and ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), so the answer is \( \frac{n}{n+1} \). Break the ratio into two smaller parts.

Which concept should I revise for this Mathematics MCQ?

( \frac{n!}{(n-1)!}=n ) and ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), so the answer is \( \frac{n}{n+1} \). Break the ratio into two smaller parts.

What exam hint can help solve this Mathematics question?

( \frac{n!}{(n-1)!}=n ) और ( \frac{n!}{(n+1)!}=\frac{1}{n+1} ), इसलिए उत्तर \( \frac{n}{n+1} \) है। अनुपात को दो छोटे भागों में तोड़ें।