फलन (f(x)=(x-2)2+5) का परिसर क्या है?
What is the range of (f(x)=(x-2)2+5)?
Explanation opens after your attempt
Correct Answer
A. \([5,\infty\))
Concept
Since ((x-2)2\ge 0), the minimum value is (5). Hence the range is \([5,\infty\)).
Why this answer is correct
The correct answer is A. \([5,\infty\)). Since ((x-2)2\ge 0), the minimum value is (5). Hence the range is \([5,\infty\)).
Exam Tip
क्योंकि ((x-2)2\ge 0), न्यूनतम मान (5) है। अतः परिसर \([5,\infty\)) है।
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