फलन (f(x)=\sqrt{x-2-1}) का परिसर क्या है?
What is the range of (f(x)=\sqrt{x-2-1})?
Explanation opens after your attempt
A. \( [0,\infty\) )
Concept
On the domain, the minimum of \(x^2-1\) is (0). As (x) grows, the square root takes all larger non-negative values.
Why this answer is correct
The correct answer is A. \( [0,\infty\) ). On the domain, the minimum of \(x^2-1\) is (0). As (x) grows, the square root takes all larger non-negative values.
Exam Tip
प्रांत में \(x^2-1\) का न्यूनतम (0) है। (x) बड़ा होने पर वर्गमूल सभी बड़े अनऋणात्मक मान लेता है।
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