फलन (f(x)=\frac{2x+1}{x-3}) का परिसर क्या है?
What is the range of (f(x)=\frac{2x+1}{x-3})?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{2}\)
Concept
If \(y=\frac{2x+1}{x-3}\), then \(x=\frac{3y+1}{y-2}\), so \(y\ne 2\). Hence the range is \(\mathbb{R}-{2}\).
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{2}\). If \(y=\frac{2x+1}{x-3}\), then \(x=\frac{3y+1}{y-2}\), so \(y\ne 2\). Hence the range is \(\mathbb{R}-{2}\).
Exam Tip
यदि \(y=\frac{2x+1}{x-3}\), तो \(x=\frac{3y+1}{y-2}\), अतः \(y\ne 2\)। इसलिए परिसर \(\mathbb{R}-{2}\) है।
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